4a1-6a? - 7a+ 4 and 3a'-7a-5, find the sum
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Answer:
Answer
(6a
2
−7a−5)÷(2a+1)
2a+1
(6a
2
+3a−10a−5)
=
2a+1
3a(2a+1)−5(2a+1)
=
2a+1
(3a−5)(2a+1)
=3a−5.
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