4a²+1/a²=2 then 8a³+1/a³=?
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Answer:
Factorisation of Algebraic Expressions
Question 1.
Factorize
i. y³ – 27
ii. x³ – 64y³
iii. 27m³ – 216n³
iv. 125y³ – 1
v. 8p3−27p3
vi. 343a³ – 512b³
vii. 64x³ – 729y³
viii. 16a3−128b3
Solution:
i. y³ – 27
= y³ – (3)³
Here, a = y and b = 3
∴ y³ – 27 = (y – 3)[y² + y(3) + (3)2]
…[∵ a³ – b³ = (a – b) (a² + ab + b²)]
= (y – 3)(y² + 3y + 9)
ii. x³ – 64y³
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