Question

4a2+12ab+9b2 divide by 4a2-9b2​

Answer 1

Step-by-step explanation:

(4a^2+12ab+9b^2)/(4a^2-9b^2)

={(2a)^2+2×2a×3b+(3b)^2}/{(2a)^2-(3b)^2}

={(2a+3b)^2}/{(2a+3b)(2a-3b)}

=(2a+3b)/(2a-3b)