Math, asked by marinaimranagha, 4 months ago

4a² - 3 ab + bc
when a=0, b=4 and c=1​

Answers

Answered by Anonymous
1

Answer:

4

Step-by-step explanation:

4a² - 3ab + bc

4 (0)² - 3 × 0 × 4 + 4 × 1

0 - 0 + 4

4

Answered by Immanuel7
1

Answer:

0

Step-by-step explanation:

2 ( a + b + c ) )² = 4 ( 3 ( ab + bc + ca ) ) ... 4a² + 4b² + 4c² + 8ab + 8bc + 8ac - 12ab - 12bc - 12ac = 0.

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