Math, asked by kkpmanikkpmani, 10 hours ago

(4a2-3ab+b2)-(6a2-5ab+3b) =_______​

Answers

Answered by purusottammanna0
3

=(4a2-6a2)+[-3ab-(-5ab)]+(b2-3ab)

=(4-6)a2+[-3ab+(+5ab)]+(1-3)b2

=[4+(-6)]a2+(-3+5)ab+[1+(-3)]b2

=-2a2+2ab-2b answer

after alphabet the 2 is squre

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