Question

4a²-4ab-c²-2bc (Factorise) plzz do it ...I want it just now...it's an urgent....plz don't spam​

Answer 1

Answer:

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Factorise :-

$\large\bold\red{ {4a}^{2} - 4ab - {c}^{2} - 2bc}$

Identity used :-

$\large\bold\red{ {x}^{2} - {y}^{2} = (x + y)(x - y) }$

$\huge\bold\red{SOLUTION}$

$\large\bold\blue{ {4a}^{2} - 4ab - {c}^{2} - 2bc}$

$\large\bold\red{ = ({4a}^{2} - {c}^{2}) - 4ab - 2bc}$

$\large\bold\red{ = ( {(2a)}^{2} - {c}^{2}) - 2b(2a + c) }$

$\large\bold\red{ = (2a + c)(2a - c) - 2b(2a + c)}$

$\large\bold\red{ = (2a + c)(2a - c - 2b)}$

$\huge \fcolorbox{black}{cyan}{Hope it helps U}$