Question

4a²-5a²,3a²,7a²
= 4a²+(-5a²)+(-3a²)+7a²
= 4a²-5a²-3a²+7a²
= -1a²-3a²+7a²
= -4a²+7a²
= 3a²​

Answer 1

Answer:

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4a²-5a²,3a²,7a²

= 4a²+(-5a²)+(-3a²)+7a²

= 4a²-5a²-3a²+7a²

= -1a²-3a²+7a²

= -4a²+7a²

= 3a²

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