Question

4a²+5b²-6ab,3ab,6a²-2b² and 4b²-5ab

Answer 1

Answer:

The solution to this problem can be done this way: –

Given,

4a² +5b² +6ab ; 3ab ; 6a² – 2b² ; 4b² – 5ab

Vertical method: –

4a² +5b² +6ab

+ 3ab

6a² – 2b² +0ab

4b² – 5ab

10a² +7b² +4ab

Horizontal method: –

4a² +5b² +6ab + (3ab) + (6a² – 2b²) + (4b² – 5ab) = 10a² +7b² + 4ab

Hope this solution will help you!