Math, asked by tanyasangwan09, 9 months ago

(4a²-6ab+9b²) (2a+3b); a=2, b=1​

Answers

Answered by ItSdHrUvSiNgH
17

Step-by-step explanation:

(4a²-6ab+9b²) (2a+3b); a=2, b=1

[4(4)-6(2)(1)+9(1)] [2(2)+3(1)]

[16-12+9] [4+3]

[13] [7]

91

Answered by Anonymous
13

Answer:

(4a {}^{2}  - 6ab + 9b {}^{2} )(2a + 3b) \\ (4(2) {}^{2}  - 6 \times 2 \times 1 + 9(1) {}^{2} )(2 \times 2 + 3 \times 1) \\ (16 - 12 + 9)(4 + 3) \\ (13)(7) \\ 91 \\  \\ here \: is \: your \: solution

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