4a²-9b²-16c²+24bc factorise
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4a²-9b²-16c²+24bc
=(2a)²-(3b)²-(4c)²+24bc
=(2a)²-{(3b)²-24bc + (4c)²}
=(2a)²-{(3b)²-(4c)²}
=(2a)²-(3b+4c)(3b-4c)
kaira1818:
i m sorry i have made a mistake in the 3rd step
so my ans is wrong
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