Question

4a2+B2+14a -7b-4ab+12

Answer 1

4a²+b²-4ab+14a-7b+12

=(2a-b)²+7(2a-b)+12

Let 2a-b=z

Z²+7z+12=0

Z²+3z+4z+12=0

(Z+3)(z+4)=0

Z=-3,-4

When z=-3

2a-b=-3

2a-b+3=0

When z=-4

2a-b+4=0