4a² + b²+ 25c² - 4ab - 10bc + 20ca
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4a2 + b2 + 25c2
4ab−10bc+20ca
= (2a)2 + (-b)2 +(5c)2
= 2×2a×(−b)+2×(−b)×5c+2×5c×2a
Using, (a+b+c)
2=a2 + b2 +c2+2ab+2bc+2a
= (2a-b+5c)2
hence the answer is
=(2a−b+5c)(2a−b+5c)
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