Question

4a²+b²+25c²-4ab-10bc+20ca. factorise

Answer 1

$4a {}^{2} + b {}^{2} + 25c {}^{2} - 4ab - 10bc + 20ca$
$(2a) {}^{2} + ( - b) {}^{2} + (5c) {}^{2} + 2 \times 2a \times ( - b) + 2 \times ( -b ) \times 5c + 2 \times 5c \times 2a$
$( 2a - b + 5c) {}^{2}$

Answer 2

Answer:

(2a-b+5c)(2a-b+5c)

Step-by-step explanation:

4a²+b²+25c²-4ab-10bc+20ca

(2a)²+(-b)²+(5c²)+2*2a*(-b)+2*(-b)*5c+2*5c*2a

(2a-b+5c)²

(2a-b+5c)(2a-b+5c)

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