Question

4a²b²-1, Factorize the given equation.

Answer 1

Hey

Question

4a²b²-1, Factorize the given equation.


Answer

∆ Step 1 : Bring all the values in the form of Square on the whole..

so

4a²b² = (2ab)²

1 = 1² as 1² equals 1 so the value doesn't changes

∆ Step 2: Think a suitable Formula


If we think then it's based on a simple formula

${a}^{2} - {b}^{2} \\ (a + b)(a - b)$

step 3: set it on a formula


(2ab)² -1²

(2ab +1)( 2ab -1)


Thanks

@Be Brainly

Answer 2

Answer:

( 2ab + 1 )( 2ab - 1 )

Step-by-step explanation:

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We know the algebraic identity:

x² - y² = ( x + y )( x - y )

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4a²b² - 1

= ( 2ab )² - 1²

= ( 2ab + 1 )( 2ab - 1 )

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