Question

4a³+20a²+16a by 4a=
=
=.

Answer 1

Step-by-step explanation:

GIVEN:-

$4 {a}^{3} + 20 {a}^{2} + 16a$

TAKE 4a COMMON FROM EQN

$4a( {a}^{2} + 5a + 4)$

NOW FROM QUESTION IT SHOULD BE DIVIDED BY 4a

so the solution is

$= ( {a}^{2} + 5a + 4) = (a + 4)(a + 1)$