Math, asked by mg761956, 9 months ago

4ab + 2mb + 4an + 2mn factorise

Answers

Answered by nikhil719

1

Answer:

(2b + 2n) (2a + m)

Step-by-step explanation:

4ab + 2mb + 4an + 2mn

2b(2a +m) 2n(2a +m)

(2b +2n) (2a+m)

Answered by aryanparasramka

1

Answer: First take 4ab and 4an common and 2mb and 2mn common

Step-by-step explanation:

(4ab + 4an)(2mb+2mn)

=> 4a(b+n) 2m(b+n)

=> (b + n)(4a + 2m)

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