Physics, asked by kchauhan9045, 1 month ago

4Abody is released Jum a height of 2om. If a = 10 m/s calculate the relocity of the body when it hits the ground Also calculate the time​

Answers

Answered by ankitabareth200787
1

Answer:

Correct option is

A

20 m/s, 2 s

Given, initial velocity of ball, u=0

Final velocity of ball, v=?

Distance through which the balls falls, s=20m

Acceleration a=10ms−2

Time of fall, t=?

We know

v2−u2=2as

or v2−0=2×10×20=400 or v=20ms−1

Now using v=u+at we have

20=0+10×t or t=2s

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