Question

+4apq + 6bpq
c. x2 – ax – bx + ab
d. x(a - b) + 2y(b − a) + 3z(a - b)2
è. a3b2 + a2b3 – ab4 + ah​

Answer 1

Answer:

c. x2 – ax – bx + ab

Step-by-step explanation:

We need to factorise x

2

−ax−bx+ab

It can be written as (x

2

−ax−bx+ab)=x(x−a)−b(x−a)=(x−b)(x−a)

Thus factors are x−a,x−b.

Answer 2

Step-by-step explanation:

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