Math, asked by asthamahakalkar, 7 months ago

(4ax + 3y)2-(4ax - 3y)2 = 48axy,prove that

Answers

Answered by kavinsiddhu758
5

Answer:

\left(4ax+3y\right)^2-\left(4ax-3y\right)^2 = 48axy\\= 16a^2x^2+24axy+9y^2-\left(4ax-3y\right)^2 = 48axy\\= 16a^2x^2+24axy+9y^2-\left(16a^2x^2-24axy+9y^2\right) = 48axy\\= 16a^2x^2+24axy+9y^2-16a^2x^2+24axy-9y^2 = 48axy\\= 48axy = 48axy

Hence Proved !

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Answered by sindhupaila2007
2

Step-by-step explanation:

(4ax+3y)^2-(4ax-3y)^2=48axy

=16a^2x^2+9y^2+2*4ax*3y-16a^2x^2-9y^2+2*4ax*3y=48axy

=24axy+24axy=48axy

=48axy=48axy

hence proved

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