За + 4b = 7 За - 4b = - 1 by using cross multiplication method
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Class 10
>>Maths
>>Pair of Linear Equations in Two Variables
>>Algebraic Methods of Solving a Pair of Linear Equations
>>Solve by cross multiplicati...
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Solve by cross multiplication method:
4x−5y=−7
4x−y=5
Medium
Solution
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Correct option is
C
x=2,y=3
Given equation are
4x−5y+7=0
4x−y−5=0
Comparing that equation
a
1
x+b
1
y+c
1
=0
a
2
x+b
2
y+c
2
=0
Then,
a
1
=4,b
1
=−5,c
1
=7
a
2
=4,b
2
=−1,c
2
=−5
By cross multiplication method,
b
1
c
2
−b
2
c
1
x
=
c
1
a
2
−c
2
a
1
y
=
a
1
b
2
−a
2
b
1
1
(−5)(−5)−(−1)(7)
x
=
(7)(4)−(−5)(4)
y
=
(4)(−1)−(4)(−5)
1
25+7
x
=
28+20
y
=
−4+20
1
32
x
=
48
y
=
16
1
x=
16
32
and y=
16
48
=3
x=2 and y=3
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