Question

(4b²/b²-9)-(3/y-3)=(2y/y+3)
Find the value of B and Y.
With checking ..

Answer 1

Answer:

Let's solve for b.

4b2

b2

−9−(

3

y

−3)=

2y

y

+3

Step 1: Multiply both sides by y.

−2y−3=5y

Let's solve for y.

4b2

b2

−9−(

3

y

−3)=

2y

y

+3

Step 1: Multiply both sides by y.

−2y−3=5y

Step 2: Add -5y to both sides.

−2y−3+−5y=5y+−5y

−7y−3=0

Step 3: Add 3 to both sides.

−7y−3+3=0+3

−7y=3

Step 4: Divide both sides by -7.

−7y

−7

=

3

−7

y=

−3

7