Question

4b²c²-(b²+c²-a²)² resolve into factors​

Answer 1

Answer:

4b^2c^2-(b^2+c^2-a^2)

=(2bc)^2-(b^2+c^2-a^2)

=(2bc+b^2+c^2-a^2){2bc-(b^2+c^2-a^2)}

={(b+c)^2-(a)^2}{2bc-b^2-c^2+a^2}

=(b+c+a)(b+c-a){a^2-(b^2-2bc+c^2)}

=(a+b+c)(b+c-a){(a)^2-(b-c)^2}

=(a+b+c)(b+c-a)(a+b-c){a-(b-c)}

=(a+b+c)(b+c-a)(a+b-c)(a-b+c)