(4b³-6b-10)x(2b³+5b-1)
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Answer:
(4b3−6b−10)(x)(2b3+5b−1)
=((4b3−6b−10)(x))(2b3+5b+−1)
=((4b3−6b−10)(x))(2b3)+((4b3−6b−10)(x))(5b)+((4b3−6b−10)(x))(−1)
=8b6x−12b4x−20b3x+20b4x−30b2x−50bx−4b3x+6bx+10x
=8b6x+8b4x−24b3x−30b2x−44bx+10x
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