4b³-6b²+10b-15
What is the solution
Answer is (2b²+5)(2b-3)
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(2b - 3) (2b² + 5)
Step-by-step explanation:
You need factorization, I suppose.
Now, 4b³ - 6b² + 10b - 15
= 4b³ - 6b² + 10b - 15
= 2b² (2b - 3) + 5 (2b - 3)
= (2b - 3) (2b² + 5)
This is the required factorization.
Note: To factorize any given term, just remember to to see by what value of the variable, the given term becomes zero. Here we see that when b = 3/2, the term is zero and that is why we have taken (2b - 3) being its factor.
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