Question

4c^2-(2a-3b+4c)^2 factorise ​

Answer 1

Answer:

12c^2- 4a^2 - 9b^2 - 12ab - 24bc - 16ac

Step-by-step explanation:

4c^2-(2a-3b+4c)^2

4c^2- [(2a)^2 + (3b)^2 + (4c)^2 + 2 * 2a * 3b + 2 * 3b * 4c + 2 * 4c * 2a]

4c^2- [ 4a^2 + 9b^2 + 16c^2 + 12ab + 24bc + 16ac]

4c^2 - 4a^2 - 9b^2 - 16c^2 - 12ab - 24bc - 16ac

:. 12c^2- 4a^2 - 9b^2 - 12ab - 24bc - 16ac

Hope it helps :)