Question

4c-[a-{a+b-c-2(b+c)}] -(c-b)

Answer 1

Hi

Here is your answer

==========================

Answer:

                 = 0

Step-by-step explanation:

= 4c- [ a - ( a + b - c - 2( a + b))] - ( c - b)

= 4c - [ a - ( a + b - c - 2b - 2c)] - c + b

= 4c - [ a - ( a - b - 3c)] - c + b

= 4c - [ a - a + b + 3c ] - c + b [ -a and +a cancelled out]

= 4c - b - 3c - c + b  [-b and + b cancelled out]

= 4c - 4c [ cancelled out]

= 0

Hope it helps U.....   :-)

Answer 2

Hey!

Answer:

Let's simplify step-by-step.

4c−(a−(a+b−c−2(b+c)))−(c−b)

Distribute the Negative Sign:

=4c−(a−(a+b−c−2(b+c)))+−1(c−b)

=4c+−a+a+b+−c+−2b−2c+−1c+−1(−b)

=4c+−a+a+b+−c+−2b−2c+−c+b

Distribute:

=4c+−a+a+b+−c+−2b+−2c+−c+b

Combine Like Terms:

=4c+−a+a+b+−c+−2b+−2c+−c+b

=(−a+a)+(b+−2b+b)+(4c+−c+−2c+−c)

Answer:

=0

:)

Step-by-step explanation: