Question

4c(-a+b+c)-3a(a+3+1+c)-(a-b+c)
with steps​

Answer 1

Answer:

-7ac + 6bc + 4c2 – 3a2 – ab – 2b2

4c (- a + b + c ) – (3a (a + b + c ) – 2b (a – b + c))

= (-4ac + 4bc + 4c2) – (3a2 + 3ab + 3ac – (2ab – 2b2 + 2bc))

=-4ac + 4bc + 4c2 – (3a2 + 3ab + 3ac – 2ab + 2b2 – 2bc)

= -4ac + 4bc + 4c2 – 3a2 – 3ab – 3ac + 2ab – 2b2 + 2bc

= -7ac + 6bc + 4c2 – 3a2 – ab – 2b2

Answer 2

Step-by-step explanation:

4c(-a+b+c)-3a(a+3+1+c)-(a-b+c)

with steps