Question

4chairs and 3tables cost 2100 and 5 chairs and 2 tables cost 1750 find the cost of one chair and one table saparately

Answer 1

Let cost of 1 chair be  Rs. x 
     cost of be table be Rs. y 
According to the question, 
cost of 4 chairs and 3 tables is  Rs. 2100
So,  4x + 3y = 2100   ……...... (i) 
Also,
 cost of 5 chairs and 2 tables is Rs.1750 
So  5x + 2y = 1750 ……….. (ii) 
from equation (i) and (ii) 
 2 × (i) gives 8x + 6y = 4200  ……… (iii) 
 3 × (ii) gives 15x + 6y = 5250 ……….. (iV) 
{(iii) - (iV)} ,
15x + 6y – 8x – 6y = 5250 – 4200 
7x = 1050 
x=1050/7  
So, x = 150 
putting the value of x in equation (ii), we get  
⇒  5(150) + 2y = 1750 
⇒750 + 2y = 1750 
⇒2y= 1750 – 750 
⇒2y = 1000
⇒ y =1000/2
⇒ y =500
Hence,  cost of each chair,x = Rs. 150 
 cost of each table,y = Rs. 500  

Answer 2

Step-by-step explanation:

Let cost of 1 chair be Rs. x

cost of be table be Rs. y

According to the question,

cost of 4 chairs and 3 tables is Rs. 2100

So, 4x + 3y = 2100 ……...... (i)

Also,

cost of 5 chairs and 2 tables is Rs.1750

So 5x + 2y = 1750 ……….. (ii)

from equation (i) and (ii)

2 × (i) gives 8x + 6y = 4200 ……… (iii)

3 × (ii) gives 15x + 6y = 5250 ……….. (iV)

{(iii) - (iV)} ,

15x + 6y – 8x – 6y = 5250 – 4200

7x = 1050

x=1050/7

So, x = 150

putting the value of x in equation (ii), we get

⇒ 5(150) + 2y = 1750

⇒750 + 2y = 1750

⇒2y= 1750 – 750

⇒2y = 1000

⇒ y =1000/2

⇒ y =500

Hence, cost of each chair,x = Rs. 150

cost of each table,y = Rs. 500

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