Question

4cm led ke gole m swarn se cover kiya jata h led or swarn ka volume barabar h to swarn ki motayi kitni h​

Answer 1

${\large\bf{\mid{\overline{\underline{Correct\: Question:-}}}\mid}}$

A ball of lead 4 cm in diameter is covered with gold. If the volume of the gold and lead are equal, then the thickness of gold ??

$\large\underline\textbf{Refer To image First.}$

$\Large\underline{\underline{\sf{Solution}:}}$

Let as per diagram

• Given OA = 2cm = radius of inner sphere = r
• OB = Radius of outer spehere = R
• CB = thickness of gold = x

Now ,

we know that,

when volume is same , Ratio of radius of Sphere is :---

$\orange{\large\boxed{\bold{r:R =1 : \sqrt[3]{2} }}}$

So,

$\green{x = (R - r)} \\ \\ \red\leadsto \: x = r( \sqrt[3]{2} - 1) \\ \\ \red\leadsto \pink{x = 2(1.259 - 1)} \\ \\ \red\leadsto \blue{x = 2 \times 0.259} \\ \\ \red\leadsto \red{\large\boxed{\bold{x = 0.518 \: cm}}}$

$\textbf{Hence, thickness of gold is 0.518cm}$

$\large\underline\textbf{Hope it Helps You.}$

Answer 2

Answer:

X=(R-r)

X=x(3√2-1)

X=2(1.259-1)

X=2×0.259

X=0.518

Step-by-step explanation: