Question

4cos²45°−sec²60°+cosec²30°+cos90°​

Answer 1

The value of 4cos²45°−sec²60°+cosec²30°+cos90°​ is 2

Step-by-step explanation:

4 cos² 45° − sec² 60° + cosec² 30° + cos90° .............. equation (1)

we know that  

value of

cos 45° = $\frac{1}{2}$

sec 60° = 2

cosec 30° = 2

cos 90° = 0

Put the known value in equation ( 1 )

= 4 *( $\frac{1}{\sqrt{2} }$ )²− 2² + 2² + 0

square of 2 is equal to 4

we get

= 4 * $\frac{1}{2}$ − 4 + 4

= 4 *0.5

= 2

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