Question

4cosa - 3sina = 5, prove that 4sina+3cosa=0

Answer 1

Answer :

3sinA+ 4cosA=5

squaring both sides,

9sin2A + 16cos2B + 24sinAcosA = 25........................(1)

4sinA - 3cosA = x

squaring both sides,

16sin^2A + 9cos^2A – 24sinAcosA  = x^2 …............(2)

Add eqns. 1) and 2)

9 + 16  = x^2

x^2 = 25

x = +5  and  x = -5

Answer 2

Answer:

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Step-by-step explanation:

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