4cosa - 3sina = 5, prove that 4sina+3cosa=0
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Answer :
3sinA+ 4cosA=5
squaring both sides,
9sin2A + 16cos2B + 24sinAcosA = 25........................(1)
4sinA - 3cosA = x
squaring both sides,
16sin^2A + 9cos^2A – 24sinAcosA = x^2 …............(2)
Add eqns. 1) and 2)
9 + 16 = x^2
x^2 = 25
x = +5 and x = -5
3sinA+ 4cosA=5
squaring both sides,
9sin2A + 16cos2B + 24sinAcosA = 25........................(1)
4sinA - 3cosA = x
squaring both sides,
16sin^2A + 9cos^2A – 24sinAcosA = x^2 …............(2)
Add eqns. 1) and 2)
9 + 16 = x^2
x^2 = 25
x = +5 and x = -5
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Answer:
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