4cot²45 -sec²60+sin²60+cos²90
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4cot²45 -sec²60+sin²60+cos²90
= 4(1)²-(2)²+(√3/2)²+0²
=4-4+3/4+0
=3/4
= 4(1)²-(2)²+(√3/2)²+0²
=4-4+3/4+0
=3/4
Answered by
1
Answer:
cot square theta
Step-by-step explanation:
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