Question

4d² = 36 find the value of d​

Answer 1

Step-by-step explanation:

f(D) = D^4-5D^2+12D+28 =0

f(D) = D^4-5D^2+12D+28 =0On putting D=-2. , f(-2). = R = 16–20–24+28=44–44=0

f(D) = D^4-5D^2+12D+28 =0On putting D=-2. , f(-2). = R = 16–20–24+28=44–44=0(D+2) is a factor of f(D).

f(D) = D^4-5D^2+12D+28 =0On putting D=-2. , f(-2). = R = 16–20–24+28=44–44=0(D+2) is a factor of f(D).D^4-5D^2+12D+28=0

f(D) = D^4-5D^2+12D+28 =0On putting D=-2. , f(-2). = R = 16–20–24+28=44–44=0(D+2) is a factor of f(D).D^4-5D^2+12D+28=0or. D^3(D+2)-2D^3–5D^2+12D+28=0

f(D) = D^4-5D^2+12D+28 =0On putting D=-2. , f(-2). = R = 16–20–24+28=44–44=0(D+2) is a factor of f(D).D^4-5D^2+12D+28=0or. D^3(D+2)-2D^3–5D^2+12D+28=0or. D^3(D+2)-2D^2(D+2)-D(D+2)+14(D+2)=0

f(D) = D^4-5D^2+12D+28 =0On putting D=-2. , f(-2). = R = 16–20–24+28=44–44=0(D+2) is a factor of f(D).D^4-5D^2+12D+28=0or. D^3(D+2)-2D^3–5D^2+12D+28=0or. D^3(D+2)-2D^2(D+2)-D(D+2)+14(D+2)=0or. (D+2)[D^3-2D^2-D+14]=0

f(D) = D^4-5D^2+12D+28 =0On putting D=-2. , f(-2). = R = 16–20–24+28=44–44=0(D+2) is a factor of f(D).D^4-5D^2+12D+28=0or. D^3(D+2)-2D^3–5D^2+12D+28=0or. D^3(D+2)-2D^2(D+2)-D(D+2)+14(D+2)=0or. (D+2)[D^3-2D^2-D+14]=0Again on putting D=-2

f(D) = D^4-5D^2+12D+28 =0On putting D=-2. , f(-2). = R = 16–20–24+28=44–44=0(D+2) is a factor of f(D).D^4-5D^2+12D+28=0or. D^3(D+2)-2D^3–5D^2+12D+28=0or. D^3(D+2)-2D^2(D+2)-D(D+2)+14(D+2)=0or. (D+2)[D^3-2D^2-D+14]=0Again on putting D=-2R=-8–8+2+14 =-16+16=0

f(D) = D^4-5D^2+12D+28 =0On putting D=-2. , f(-2). = R = 16–20–24+28=44–44=0(D+2) is a factor of f(D).D^4-5D^2+12D+28=0or. D^3(D+2)-2D^3–5D^2+12D+28=0or. D^3(D+2)-2D^2(D+2)-D(D+2)+14(D+2)=0or. (D+2)[D^3-2D^2-D+14]=0Again on putting D=-2R=-8–8+2+14 =-16+16=0(D+2)is also a factor.

f(D) = D^4-5D^2+12D+28 =0On putting D=-2. , f(-2). = R = 16–20–24+28=44–44=0(D+2) is a factor of f(D).D^4-5D^2+12D+28=0or. D^3(D+2)-2D^3–5D^2+12D+28=0or. D^3(D+2)-2D^2(D+2)-D(D+2)+14(D+2)=0or. (D+2)[D^3-2D^2-D+14]=0Again on putting D=-2R=-8–8+2+14 =-16+16=0(D+2)is also a factor.or. (D+2)[D^2(D+2)-4D(D+2)+7(D+2)]=0

f(D) = D^4-5D^2+12D+28 =0On putting D=-2. , f(-2). = R = 16–20–24+28=44–44=0(D+2) is a factor of f(D).D^4-5D^2+12D+28=0or. D^3(D+2)-2D^3–5D^2+12D+28=0or. D^3(D+2)-2D^2(D+2)-D(D+2)+14(D+2)=0or. (D+2)[D^3-2D^2-D+14]=0Again on putting D=-2R=-8–8+2+14 =-16+16=0(D+2)is also a factor.or. (D+2)[D^2(D+2)-4D(D+2)+7(D+2)]=0or. (D+2)(D+2)(D^2-4D+7)=0

f(D) = D^4-5D^2+12D+28 =0On putting D=-2. , f(-2). = R = 16–20–24+28=44–44=0(D+2) is a factor of f(D).D^4-5D^2+12D+28=0or. D^3(D+2)-2D^3–5D^2+12D+28=0or. D^3(D+2)-2D^2(D+2)-D(D+2)+14(D+2)=0or. (D+2)[D^3-2D^2-D+14]=0Again on putting D=-2R=-8–8+2+14 =-16+16=0(D+2)is also a factor.or. (D+2)[D^2(D+2)-4D(D+2)+7(D+2)]=0or. (D+2)(D+2)(D^2-4D+7)=0or. (D+2)^2[D^2-4D+4+3]=0

f(D) = D^4-5D^2+12D+28 =0On putting D=-2. , f(-2). = R = 16–20–24+28=44–44=0(D+2) is a factor of f(D).D^4-5D^2+12D+28=0or. D^3(D+2)-2D^3–5D^2+12D+28=0or. D^3(D+2)-2D^2(D+2)-D(D+2)+14(D+2)=0or. (D+2)[D^3-2D^2-D+14]=0Again on putting D=-2R=-8–8+2+14 =-16+16=0(D+2)is also a factor.or. (D+2)[D^2(D+2)-4D(D+2)+7(D+2)]=0or. (D+2)(D+2)(D^2-4D+7)=0or. (D+2)^2[D^2-4D+4+3]=0or. (D+2)^2[(D-2)^2-(√3.i)^2]=0

f(D) = D^4-5D^2+12D+28 =0On putting D=-2. , f(-2). = R = 16–20–24+28=44–44=0(D+2) is a factor of f(D).D^4-5D^2+12D+28=0or. D^3(D+2)-2D^3–5D^2+12D+28=0or. D^3(D+2)-2D^2(D+2)-D(D+2)+14(D+2)=0or. (D+2)[D^3-2D^2-D+14]=0Again on putting D=-2R=-8–8+2+14 =-16+16=0(D+2)is also a factor.or. (D+2)[D^2(D+2)-4D(D+2)+7(D+2)]=0or. (D+2)(D+2)(D^2-4D+7)=0or. (D+2)^2[D^2-4D+4+3]=0or. (D+2)^2[(D-2)^2-(√3.i)^2]=0or. (D+2)^2(D-2+√3.i)(D-2-√3.i)=0

f(D) = D^4-5D^2+12D+28 =0On putting D=-2. , f(-2). = R = 16–20–24+28=44–44=0(D+2) is a factor of f(D).D^4-5D^2+12D+28=0or. D^3(D+2)-2D^3–5D^2+12D+28=0or. D^3(D+2)-2D^2(D+2)-D(D+2)+14(D+2)=0or. (D+2)[D^3-2D^2-D+14]=0Again on putting D=-2R=-8–8+2+14 =-16+16=0(D+2)is also a factor.or. (D+2)[D^2(D+2)-4D(D+2)+7(D+2)]=0or. (D+2)(D+2)(D^2-4D+7)=0or. (D+2)^2[D^2-4D+4+3]=0or. (D+2)^2[(D-2)^2-(√3.i)^2]=0or. (D+2)^2(D-2+√3.i)(D-2-√3.i)=0Values of D are. -2 , -2 , (2-√3.i) , (2+√3.i)

hope it helps uh...

Answer 2

Answer:

it's 3

Step-by-step explanation:

4d²=36

d²= 36/4

d = √36/4

d = 6/2 ( as √36= 6 and √4 = 2 )

d =3

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