Question

4एक्स स्क्वायर +4ax+(ए स्क्वायर माइनस बी स्क्वायर )=0​

Answer 1

Answer:

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Answer 2

Answer:

Given equation

$4x {}^{2} + 4ax + a {}^{2} - b {}^{2}$

We can write

$4ax \\ = (2a + 2a + 2b - 2b )x\\ = (2a + 2b + 2a - 2b)x \\ = 2(a + b)x + 2(a - b)x$

and

$(a {}^{2} - b {}^{2} ) = (a + b)(a - b)$

So now,

$4x {}^{2}+ 4ax + a {}^{2} - b {}^{2} \\ = 4x {}^{2} + 2(a + b)x + 2(a - b)x + (a + b)(a - b) \\ = (4x {}^{2} + 2(a + b)x) + (2(a - b)x + (a + b)(a - b)) \\ = 2x(2x + (a + b)) + (a + b)(2x + (a - b)) \\ = (2x + (a + b))(2x(a - b)) \\ = (2x + a + b)(2x + a - b)$

I hope it will help.