Question

(4f+2),(6m-4),(k+1) are three consecutive even integers , (4f+2) being the smallest of them . their sum is 96. what is the value of f ?
a) 20
b)21
c)22
d)24

Answer 1

Answer:

Take the first integer as

x

. Since we are talking about the next even integer, it will come when you add two to

x

.

For example, let's say that you have

2

as the value of

x

. The next even integer is

4

, which is

x

+

2

, and the next is

6

, which is

x

+

4

.

So eventually, the equation is

(

x

)

+

(

x

+

2

)

+

(

x

+

4

)

=

66

3

x

+

6

=

66

3

x

=

66

−

6

3

x

=

60

x

=

60

÷

3

x

=

20

So

x

=

20

x

+

2

=

22

x

+

4

=

24