Question

4g carbon were heated with 8g of Sulphur,how much CS2(carbondisulphide) will be formed when the reaction is complete?What will be its percentage purity?

Answer 1

Ideally, 1 mole of C will react with 2 moles of S to form CS2 

Given, 4g of C = 4/12 = 0.33 mol  ------ 1 mol of C = 12g

 8g of S = 8/32 = 0.25 mol -------- 1 mol of S = 32 g

 

Now as we can see that 0.25 mol of S will react with 0.125 mol of C i.e. 8 gms of S will react with only 1.5 g of C. to form 9.5 gms of CS2

Hence, % purity = (Wt. of product / wt. of reactants ) *100 

 = 9.5 / (4+8) = 9.5/12 = 79.16 %

Answer 2

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