4g hydrogen reacts with 9 * 10^23 chlorine molecules
Answers
Answer:
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Explanation:
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The question is incomplete, here is the complete question:
4 g hydrogen reacts with 9×10^{23} chlorine molecules and form HCI gas. If the total pressure of the system after the reaction is 700 mmHg, what is the partial pressure of HCI?
The partial pressure of HCl is 598.5 mmHg
Explanation:
- For hydrogen gas:
To calculate the number of moles, we use the equation:
Given mass of hydrogen gas = 4 g
Molar mass of hydrogen gas = 2 g/mol
Putting values in above equation, we get:
- For chlorine gas:
According to mole concept:
number of molecules are present in 1 mole of a compound
So, number of molecules will be present in = of chlorine gas
The chemical equation for the formation of HCl follows:
By Stoichiometry of the reaction:
1 moles of chlorine gas reacts with 1 mole of hydrogen gas.
So, 1.494 moles of chlorine gas will react with = of hydrogen gas
As, given amount of hydrogen gas is more than the required amount. So, it is considered as an excess reagent.
Thus, chlorine gas is considered as a limiting reagent because it limits the formation of product.
Excess moles of hydrogen gas remaining = [2 - 1.494] = 0.506 moles
By Stoichiometry of the reaction:
1 mole of chlorine gas produces 2 moles of HCl
So, 1.494 moles of chlorine gas will produce = of HCl
Total moles of the container = [2.988 + 0.506] = 3.494 moles
Mole fraction of a substance is given by:
So,
To calculate the partial pressure of HCl, we use the equation given by Raoult's law, which is:
where,
= partial pressure of HCl = ?
= total pressure = 700 mmHg
= mole fraction of HCl = 0.855
Putting values in above equation, we get:
Learn more about number of moles and Raoult's law:
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