Question

4g of a metallic chloride contains 1.89g of the metal x. Calculate the empirical formula of the metallic chloride

Answer 1

Answer:

Explanation:

Dear student,

Please find below the solution to the query posted by you.

Given:

Mass of metal chloride = 4 g

Mass of metal X in metal chloride = 1.89 g

So,

Mass of chlorine in metal chloride = 4 − 1.89 = 2.11 g

Percentage of metal X in 4 g of metal chloride = 1.894×100 = 47.25 %Percentage of metal X in 4 g of metal chloride = 1.894×100 = 47.25 %

Percentage of chlorine in 4 g of metal chloride = 2.114×100 = 52.75 %Percentage of chlorine in 4 g of metal chloride = 2.114×100 = 52.75 %

Element Percentage Atomic Mass Number of Moles  Molar Ratio

X 47.25 64 47.2564=0.7447.2564=0.74 0.740.74=10.740.74=1

Cl 52.75 35.5 52.7535.5=1.4852.7535.5=1.48 1.480.74=21.480.74=2

Empirical formula of the metal chloride = XCl2

Hope this information will clear your doubt regarding empirical formula of compounds.

In case of any doubt just post your query on the forum and our experts will try to help you as soon as possible.

Answer 2

Answer:

:Mass of metal chloride = 4 g

Mass of metal X in metal chloride = 1.89 g

So,

Mass of chlorine in metal chloride = 4 − 1.89 = 2.11 g

Percentage of metal X in 4 g of metal chloride = 1.894×100 = 47.25 %Percentage of metal X in 4 g of metal chloride = 1.894×100 = 47.25 %

Percentage of chlorine in 4 g of metal chloride = 2.114×100 = 52.75 %Percentage of chlorine in 4 g of metal chloride = 2.114×100 = 52.75 %

Element Percentage Atomic Mass Number of Moles  Molar Ratio

X 47.25 64 47.2564=0.7447.2564=0.74 0.740.74=10.740.74=1

Cl 52.75 35.5 52.7535.5=1.4852.7535.5=1.48 1.480.74=21.480.74=2

Empirical formula of the metal chloride = XCl2