4g of copper was dissolved in conc. hno3. the copper nitrate thus obtained gave 5g of its oxide on strong heating the equivalent weight of copper is
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Answered by
13
Hello Dear.
Given in the question:- 4 g of copper gave 5 g of copper oxide when dissolved.
Therefore for finding the equivalent weight, Mass of oxygen in oxides are
Now weight of Oxygen in CuO :- 5 g - 4 g = 1
∴We know, weight of Cu which combine 1 g of O₂ = 4
Now weight of Cu which react 8 g of Oxygen = 4 x 8
=32
Hence equivalent weight of Cu is 32.
Hope it Helps.
Given in the question:- 4 g of copper gave 5 g of copper oxide when dissolved.
Therefore for finding the equivalent weight, Mass of oxygen in oxides are
Now weight of Oxygen in CuO :- 5 g - 4 g = 1
∴We know, weight of Cu which combine 1 g of O₂ = 4
Now weight of Cu which react 8 g of Oxygen = 4 x 8
=32
Hence equivalent weight of Cu is 32.
Hope it Helps.
Answered by
1
Explanation:
5 gm CuO,4gm Cu and 1 gm O be present.
Empirical formula =CuO of oxide
In this oxide, oxidation no. of Cu=+2
Equivalent weight=Molecular weightOxidation no.=63.52≈31.75
But equivalent weight should be an integral no.=32.
=9.65A
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