Question

4g of hydrogen gas combines with 32g of oxygen gas, how much water will be produced? (write the word equation also)

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Answer 1

Explanation:

4g Of hydrogen reacts with 32g of oxygen to produce 36g of water. Answer would be: 2 moles of water [36 g] because O2 available is 32g and it acts as limiting reagent/reactant and hydrogen is excess reactant.

Answer 2

Given:

Hydrogen gas = $4$ g

Oxygen gas = $32$ g

To find:

Amount of water produced

Step-by-step explanation:

The molecular masses of hydrogen, oxygen and water are $2$ g/mole, $32$ g/mole and $18$ g/mole respectively.

$2H_2\;+\;O_2\;\rightarrow\;2H_2O$

$2\times2=4\;$ g of hydrogen reacts with $1\times32=32$ g of oxygen to form $2\times18=36$ g of water.

Answer:

$4$ g of hydrogen gas combines with $32$ g of oxygen gas to form $36$ g of water.