Question

4g of hydrogen reacts with 20g of oxygen to form water the mass of water formed is

Answer 1

Given that ,

4g of hydrogen =2moles

20g of hydrogen = 0.625 moles

One mole of hydrogen required 0.5 moles of oxygen

1.25 mole of hydrogen required 0.625 moles of oxygen

Thus , Oxygen us a limiting reagent

Total mass of water formed is 1.25*18 = 22.5g

Answer 2

The mass of water formed is $22.5 \mathrm{gm}$.

Chemical reaction for water is given as:

Two hydrogen atoms and one oxygen atom make up a water molecule (also known as dihydrogen monoxide).

$\begin{aligned}\quad \mathrm{H}_{2} &+\frac{1}{2} \mathrm{O}_{2} \rightarrow \mathrm{H}_{2} \mathrm{O} \\\text { Mass-4g } & 20 \mathrm{~g} \\\text { Moles-2 } & 0.625\end{aligned}$

Given:

4g of hydrogen reacted with 20g of oxygen.

Explanation:

1 mole of $\mathrm{H}_{2}$ requires $0.5$ moles of $\mathrm{O}_{2}$.

Therefore,

$1.25$ moles of $\mathrm{H}_{2}$ requires $0.625$ moles of $\mathrm{O}_{2}$.

Similarly,

$\mathrm{O}_{2}$ is a limiting reagent.

$0.5$ mole $\mathrm{O}_{2} \rightarrow 1$ mole $\mathrm{H}_{2} \mathrm{O}$

$0.625$ mole $\mathrm{O}_{2}=\frac{1 \times 0.625}{0.5}$ moles $\mathrm{H}_{2} \mathrm{O}$.

$=1.25$ moles of $\mathrm{H}_{2} \mathrm{O}$

Therefore, mass of $\mathrm{H}_{2} \mathrm{O}$ formed is  $1.25 \times 18=22.5 \mathrm{gm}$

To know more about molecular mass, here

https://brainly.in/question/31416201?msp_poc_exp=2

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