4g of NaOH was dissolved in water and the solution was made up to 1000ml the whole of this will neutralize completely
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Answer:
The correct answer is option B.
Explanation:
Mass of NaOH = 4g
Molecular mass of NaOH = 40g/mol
Number of mole of NaOH = 4/40 =0.1 moles
Molarity = number of mole of solute /volume of solution in liter
= 0.1 × 1000/1000
= 0.1M
Now find normality
Normality = n-factor × molarity
= 1 × 0.1 = 0.1N
In case of complete neutralisation,
n- factor of acid × mole of acid = 1 × 0.1 = 0.1
For H2SO4 , n -factor = 2
Or mole of acid = 0.1/2 = 0.05
Now put the values:
Mole of acid = 2.5 × 20/1000 = 50/1000 = 0.05
Thus it satifies the second option. Which is correct answer.
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