Question

4g of sodium chloride is dissolved in 20g of water. what is mass by mass percentage of solution

a.4%
b.40%
c.20%
d.25%​

Answer 1

Answer:

The true answer is 16.6667 %

Explanation:

(4g/24g)*100%

=16.67 %

so, all options you gave are wrong.

Answer 2

Provided that:

• Sodium chloride = 4 g as solute
• Water = 20 g as solvent

To calculate:

• The concentration in the terms of mass by mass percentage of the solution.

Solution:

• The concentration in the terms of mass by mass percentage of the solution = 16.67 %

Using concept:

• Mass by mass percentage formula to calculate the concentration of the solution.

Using formula:

• ${\small{\underline{\boxed{\pmb{\sf{Mass \: \% \: = \dfrac{Mass_{solute}}{Mass_{solution}} \times 100 \: \%}}}}}}$

Knowledge required:

• "Solute" is present in "less quantity."

• "Solvent" is present is "excess quantity."

• "Solution" consists of two components that are "solute and solvent."

• The component of the solution that dissolves the other component in it is called the "solvent."

• The component of the solution that is dissolved in the solvent is called "solute."

Required solution:

~ Firstly let us calculate the mass of the solution by using suitable formula!

We know that solution is made up of two components that are solute and solvent.

Therefore,

=> Solution = solute + solvent

↦ Solution = 4 + 20

↦ Solution = 24 g

• Henceforth, the mass of the solution = 24 grams!

~ Now by using suitable formula let us find out the mass by mass percentage!

${\sf{\mapsto Mass \: \% \: = \dfrac{Mass_{solute}}{Mass_{solution}} \times 100 \: \%}}$

${\sf{\mapsto Mass \: \% \: = \dfrac{4}{24} \times 100 \: \%}}$

${\sf{\mapsto Mass \: \% \: = \dfrac{1}{6} \times 100 \: \%}}$

${\sf{\mapsto Mass \: \% \: = \dfrac{100}{6}}}$

${\sf{\mapsto Mass \: \% \: = 16.66 \: \%}}$

• Henceforth, mass by mass percentage is 16.66 percentage that is approximately equal to 16.67 %!

Dear user, according to the calculations and the formula answer is 16.67 % Therefore, no option is correct.