Question

4g of solid NaOH was dissolved in water and the solution was made up of 1000 ml. The whole of this will neutralize completely

(1) 100 ml of 1 M H2SO4
(2) 20 ml of 2.5 M H2SO4
(3) 20 ml of 1.5 M H2SO4
(4) 30 ml of 5 M H2SO4

Answer 1

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The answer is (2) 0.02 l of 2.5M acid

Given

NaOH sample mass = 4gm

NaOH molar masd = 40 gm

n = 4÷ 40 = 0.1 mol

M concentration of NaOH = 0.1 ÷ 1 L = 0.1 M

NaOH solution volume = 1000ml

Neutralize with H2SO4

The equation is

2NaOH + H2SO4 = Na2SO4 + 2H2O

Mb = 0.1 M

Vb = 1

b = 2 from the equatio

Ma×Va ÷ a = ????

Law of neutralization is

Mb ×Vb ÷ b ( base) =

Ma × Va ÷ a (acid)

0.1 × 1 ÷ 2 = 0.05

So, acid must be equal 0.05

1) 0.1 × 1 ÷ 1 = 0.1

2) 0.02 × 2.5 ÷ 1 = 0.05

3) 0.02 × 1.5 ÷ 1 = 0.03

4) 0.03 × 5 ÷ 1 = 0.15

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