Question

4g of solid naoh was dissolved in water and the solution was made upto 1000
ml the whole of this will neutralized completely
(1)100ml of 1M h2so4
(2)20ml of 2.5M h2so4
(3)20ml of 1.5M h2so4
(4)30ml of 5M h2so4
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Answer 1

Answer:

Explanation:

4g of solid NaOH was dissolved in water and the solution was made up to 1000 ml. The whole of this will neutralised completely

1 . 100ml of 1 M H2SO4

2.20 ml of 2.5M H2SO4✔

3. 20 ml of 1.5 M H2SO4

4.30 ml of 5 M H2SO4.

Answer 2

Answer:

The answer is (2) 0.02 l of 2.5M acid

Given

NaOH sample mass = 4gm

NaOH molar masd = 40 gm

n = 4÷ 40 = 0.1 mol

M concentration of NaOH = 0.1 ÷ 1 L = 0.1 M

NaOH solution volume = 1000ml

Neutralize with H2SO4

The equation is

2NaOH + H2SO4 = Na2SO4 + 2H2O

Mb = 0.1 M

Vb = 1

b = 2 from the equatio

Ma×Va ÷ a = ????

Law of neutralization is

Mb ×Vb ÷ b ( base) =

Ma × Va ÷ a (acid)

0.1 × 1 ÷ 2 = 0.05

So, acid must be equal 0.05

1) 0.1 × 1 ÷ 1 = 0.1

2) 0.02 × 2.5 ÷ 1 = 0.05

3) 0.02 × 1.5 ÷ 1 = 0.03

4) 0.03 × 5 ÷ 1 = 0.15

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