Question

4g of solute are dissolved in 40g of water to form a saturated solution at 25 degree Celsius. calculate the solubility of solute.

Answer 1

solubility at 25 degree celsius=100*4/40
                                               =40/4
                                               =10g
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Answer 2

Answer: The solubility of solute in water at 25 ° C is 10 grams per 100 g water.

Explanation:

Mass of the solute = 4 grams

Mass of the solvent = 40 grams

$Solubility=\frac{\text{mass of solute}}{\text{mass of solvent}}\times 100$

$=\frac{4}{40}\times 100=10$ grams per 100 g water

So, the solubility of solute in water at 25 ° C is 10 grams per 100 g water.