4h2o + 3fe = fe3o4 + 4h2 {weight of h20 is given 27 g}
In above reaction :
According to stoichiometry, 4 moles of h2o weighing 27g gives 4 moles of h2
But according to mole concept, 1.5 moles of h20 weiging 27 g gives 1.5 moles of h2
How is this possible ?
Please clear my doubt..
Answers
Answered by
4
Answer:
4h2o + 3fe = fe3o4 + 4h2 {weight of h20 is given 27 g}
In above reaction :
According to stoichiometry, 4 moles of h2o weighing 27g gives 4 moles of h2
But according to mole concept, 1.5 moles of h20 weiging 27 g gives 1.5 moles of h2
How is this possible ?
Please clear my doubt..
hope it is helpful to you Mark me as brainallist plz ✌️✌️❣️
Similar questions