4HCl + A + MnCl2 + Cl2 + 2H2O. In this reaction the change in oxidation state of the metal present in A is (A) +2 to - 2 (B) + 4 to + 6 (C) - 1 to + 3 (D) + 4 to + 2
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Answer:
(d) + 4 to + 2
Explanation:
4HCl + MnO₂ -> MnCl₂ + Cl₂ + 2H₂O
The oxidation state of Mn in MnO₂ is +4
The oxidation state of Mn in MnCl₂ is +2
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