4HCl(aq) + MnO2(6) 2H20, + MnCl2(aq) + Cl2(o according to given reaction how many gram of MnO2 is required to completely react with 25mL 0.5MHCI.
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4HCl + MnO2 ----> 2H2O + MnCl2+ Cl2. for this reaction determine the mass of HCl that will react with 5 gm of MnO2. MnO2 = 54.94 + 2 ( 15.99 ) = 86.92 g of MnO2
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