Question

4i^8-3i^9+3/3i^11-4i^10-2 express in form of a+ib state value of a and b​

Answer 1

Answer:

$\bf\:\frac{23}{13}+i\frac{17}{13}$

Step-by-step explanation:

$\frac{4i^8-3i^9+3}{3i^{11}-4i^{10}-2}$

using

$\boxed{i^{4n}=1}$

$\boxed{i^{4n-1}=-i}$

$\boxed{i^{4n-2}=-1}$

$\boxed{i^{4n-3}=i}$

$=\frac{4(1)-3i+3}{3i^3-4i^2-2}$

$=\frac{4-3i+3}{3(-i)-4(-1)-2}$

Multiply both numerator and denonminator by 2+3i

$=\frac{7-3i}{2-3i}\times\:\frac{2+3i}{2+3i}$

$=\frac{14+21i-6i+9}{2^2-(3i)^2}$

$=\frac{23+17i}{4+9}$

$=\frac{23+17i}{13}$

$=\frac{23}{13}+i\frac{17}{13}$

Answer 2

ITS IS CORRECT ANS FOR YOU